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SE1 - SE2 - SE3 - SE4 - SE5 - SE6 - SE7 - SE8 - SE9 - SE10 |
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< 3.8 |
Let us have a
sample of 20 numbers with a mean value of 3.5 and a variance of 1.2.
What is the probability that the mean value of the underlying population is greater 3.8. |
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The FunLog++ interpreter calculates the probability for an X value according to the t-test. |
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| moments([3.5, 1.2],20,_,_)<3.8 | The FunLog++ interpreter evaluates
the </2 relation and generates an appropriate probability. Click on
the message link to see the result of this calculation which is displayed.
sUcCeSs @ (0.9681) |
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FunLog++introduction - glossary - language - library - semiknown - dynamic |
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